Golang Pointers
Nerdherd
Posted on September 16, 2024
Coming from Ruby, thinking about Golang pointers does require a shift in thinking.
In Ruby,
- Variables are references to objects.
- When you assign one variable to another, both variables point to the same object.
- Changing an object through any variable will be reflected across all references
# Variable array_a is a reference to an Array object
array_a = [1,2,3]
# array_b and array_c now points to the same Array object as array_a
array_b = array_a
array_c = array_a
# Updating array_b will update the underlying Array object defined by 'array_a'
# array_a, array_b and array_c will have the same output
array_b << 4
puts "a: " + array_a
puts "b: " + array_b
puts "c: " + array_c
# output
# a: [1,2,3,4]
# b: [1,2,3,4]
# c: [1,2,3,4]
In Go:
- Variables can store actual values or pointers (memory addresses) to values.
- Assigning one variable to another will copy the value
- This results in two independent variables
- Pointers allow you reference the same data from multiple variables.-
Go pointers (
*Type
) references the memory address, where the data is stored.
- It would like something like
*string=0x14000114180
.Go values (
Type
) holds the actual data
- Copying will create a new independent instance
// main.go
package main
import "fmt"
func main() {
// Create an array of length 4, with initial values [1, 2, 3, 0]
array_a := [4]int{1,2,3}
// 'array_b' references the same underlying array as 'array_a'
array_b := array_a
array_c := array_c
array_b[3] = 4
fmt.Println("array_a: " array_a)
fmt.Println("array_b: " array_b)
fmt.Println("array_c: " array_c)
}
// output
// array_a: [1 2 3 0]
// array_b: [1 2 3 4] <-- only b changed
// array_c: [1 2 3 0]
To achieve the same result as ruby, we would need to ensure that we are not "copying" the value of array_a
to array_b
and array_c
.
Instead, we would need to assign array_b
and array_c
a pointer to array_a
.
// main.go
package main
import "fmt"
func main() {
// Create an array of length 4, with initial values [1, 2, 3, 0]
array_a := [4]int{1,2,3}
// 'array_b' and 'array_c' is a pointer to the memory address that stores the value of 'array_a'
array_b := &array_a
array_c := &array_c
array_b[3] = 4
// Since array_a does not store a pointer, we print it directly
// array_a (value)
// +-------------------+
// | [1, 2, 3, 4] |
// +-------------------+
// ^
// |
// &array_a (address) <--- array_c, array_b (pointers)
//
fmt.Println("array_a: ", array_a)
// '*array_b' is called dereferencing
// Since 'array_b' stores the pointer to 'array_a', weneed to "dereference it"
fmt.Println("array_b: ", *array_b)
fmt.Println("array_c: ", *array_c)
}
// output
// array_a: [1 2 3 4]
// array_b: [1 2 3 4]
// array_c: [1 2 3 4]
💖 💪 🙅 🚩
Nerdherd
Posted on September 16, 2024
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