Common assertions for Java collections in AssertJ

iuriimednikov

Yuri Mednikov

Posted on April 3, 2020

Common assertions for Java collections in AssertJ

Hello! As part of Java collection series, I decided to write this small post to list some of most common assertion methods from AssertJ, that can be used to test Java collections.

Common collection assertions

This section presents most common assertions, used with Java collections. Examples are illustrated using array-based lists, that are most used Java data structures.

Collection contains the element

Basic situation is to check if the collection contains or does not contain the specific element. AssertJ validates this using contains()/doesNotContain() element which have overloaded versions:

  • contains(E e, int index) = checks that the element presents on the specific position
  • contains(E... elements) = accepts varargs, e.g. one or more elements and checks for their presence in any order

Take a look on the code snippet below:

@Test
public void containsElementTest(){
    List<Integer> numbers = Lists.newArrayList(1, 52, 12, 39, 45, 98, 100, 565, 6, 13);
    assertThat(numbers).contains(12);
    assertThat(numbers).doesNotContain(50);
}
Enter fullscreen mode Exit fullscreen mode

Collection contains elements in any order

In order to verify, that collection contains a group of elements, it is possible to use two scenarios:

  • Use contains(E.. elements) method and supply elements as varargs
  • Use contains(Iterable i) method that accepts another collection and validates that all elements are contained inside the original one in any order

Here is the example of using containsAll():

@Test
public void containsAllElementsNoMatterOrderTest(){
    List<Integer> numbers = Lists.newArrayList(1, 52, 12, 39, 45, 98, 100, 565, 6, 13);
    List<Integer> values = Lists.newArrayList(52, 39, 12, 1, 100);
    assertThat(numbers).containsAll(values);
}
Enter fullscreen mode Exit fullscreen mode

Collection contains elements in the specific order

Another case is to validate, that the collection contains not only all specified elements, but also keep the specific order. To do this, it is possible to use containsExactlyElementsOf() method. It accepts an iterable and verifies that actual collection contains all the elements of the given iterable and nothing else in the same order.

Take a look on following example:

@Test
public void containsAllElementsInOrderTest(){
    List<Integer> numbers = Lists.newArrayList(1, 52, 12, 39, 45, 98, 100, 565, 6, 13);
    List<Integer> values = Lists.newArrayList(numbers);
    assertThat(numbers).containsExactlyElementsOf(values);
}
Enter fullscreen mode Exit fullscreen mode

Collection contains no duplicates

Not all Java collections allows duplicates: sets, for example, check for inserted elements and do not allow duplicates. Other collections, like lists, do not offer this functionality. In this case, when you need to asserts that the collection does not have duplicate elements, it is advised to use doesNotHaveDuplicates() method:

@Test
public void noDuplicatesTest(){
    List<Integer> numbers = Lists.newArrayList(1, 52, 12, 39, 45, 98, 100, 565, 6, 13);
    assertThat(numbers).doesNotHaveDuplicates();
}
Enter fullscreen mode Exit fullscreen mode

Collection contains the element only once

The extended case of the last situation is to check that element is presented only once. Technically, contains() method allows duplicate entities, so to check that element does not repeat, use containsOnlyOnce() assertion.

Observe the code snippet below:

@Test
public void containsOnlyOnceTest(){
    List<Integer> numbers = Lists.newArrayList(1, 1, 52, 12, 12, 45, 45);
    assertThat(numbers).containsOnlyOnce(52);
}
Enter fullscreen mode Exit fullscreen mode

Source code

You can find the full source code for this post in this github repository. If you have questions regarding this post, don't hesitate to contact me. Have a nice day!

💖 💪 🙅 🚩
iuriimednikov
Yuri Mednikov

Posted on April 3, 2020

Join Our Newsletter. No Spam, Only the good stuff.

Sign up to receive the latest update from our blog.

Related