Converting a decimal number to its binary, octal or hexadecimal value is easier than it looks. A simple way to do this is using the bin, oct and hex functions directly:

n = 97

print(bin(n))
print(oct(n))
print(hex(n))

Result:

0b1100001
0o141
0x61

Note that we have two digits of standardization at the beginning of the results, to solve this, we can slice it as follows:

n = 97

print(bin(n)[2:])
print(oct(n)[2:])
print(hex(n)[2:])

Result:

1100001
141
61