Transform List to Varargs in Java

Hello everyone 😁. For this article we will be transform List to Varargs.

Firstly, I want to show example of varargs in argument of method.
Normally, the varargs is represent as a iterator type that you can loop each element.

class Main {  
  public static void main(String args[]) { 
    System.out.println(concatString("Hello", "world!")); 
  }

  public static String concatString(String... words) {
    StringBuilder sb = new StringBuilder();
    for (String str : words) {
      sb.append(str);
      sb.append(" ");
    }
    return sb.toString().trim();
  }
}

But if you seen some library, They receive varargs as a parameter too!. So if you have list of data, you can transform it to array and thrown it to that method.

This is example of code that will show you how to transform it. ✌

import java.util.List;

class Main {  
  public static void main(String args[]) { 
    List<String> words = List.of("Hello", "world!");
    String result = concatString(words.toArray(new String[words.size()]));
    System.out.println(result);
  }

  public static String concatString(String... words) {
    StringBuilder sb = new StringBuilder();
    for (String str : words) {
      sb.append(str);
      sb.append(" ");
    }
    return sb.toString().trim();
  }
}

That's it. This is how we can use List as argument of method that received varargs.

Thank you very much for reading. 😄

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Transform List to Varargs in Java

Thanaphoom Babparn

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