SPO600 - Lab 4 - Option 1
Thanh Van
Posted on November 4, 2021
In the previous lab, we were working with Math in Assembly Language. However, in this lab, we will be working on Assembly Language String. We have four options to pick this time, and implement two of them:
- Adding Calculator
- Data Input Form
- Hexdump
- Screen Colour Selector
For the first option, I choose Adding Calculator to work on.
Instruction
- Create a subroutine which enables the user to enter two numbers of up to two digits. Indicate where the cursor is, and allow the user to use the digit keys (0-9), backspace, and enter keys. Return the user's input value in the accumulator register.
- Using this subroutine, write a program which add the two numbers (each of which is in the range 0-99) and print the result.
Program
; ======== variables for screen input/output ========
define SCINIT $ff81 ; initialize/clear screen
define CHRIN $ffcf ; input character from keyboard
define CHROUT $ffd2 ; output character to screen
define SCREEN $ffed ; get screen size
define PLOT $fff0 ; get/set cursor coordinates
; ======== variables for key ========
define RIGHT $81
define LEFT $83
define ENTER $0d
define BACKSPACE $08
; numbers given by user
define NUM1 $15;
define NUM2 $16;
jsr SCINIT
; prompts to get input from user, do calculation and print the result
mainLoop:
ldy #$00
jsr firstNumPrint ; ask for input for first number
jsr getNum; get the first number
jsr storeFirstNum ; then store the first number
ldy #$00
jsr secondNumPrint ; ask for input for second number
jsr getNum; get the second number
jsr storeSecondNum ; store the second number
ldy #$00
jsr resultPrintString ; print a string 'Result'
jsr printResult ; print the result
jmp mainLoop ; go back to the first step
getNum:
sec
jsr PLOT
ldx #$15
clc
jsr PLOT
getNumLoop:
sec
jsr PLOT
jsr CHRIN
charCheck:
cmp #BACKSPACE ; if user enter backspace, it erase the #$15 digit
beq move_back
cmp #RIGHT ; if user enter right arrow, it goes to the first digit
beq move_right
cmp #LEFT ; if user enter left arrow, it goes to the second digit
beq move_left
cmp #ENTER ; if user enter enter, it goes to the next process
beq move
drawNum:
; check whether user enters number (#$30-#$39)
cmp #$30
bcc getNumLoop
clc
cmp #$3a
bcs getNumLoop
jsr CHROUT
sec
jsr PLOT
cpx #$17
bne getNumLoop
dex
clc
jsr PLOT
jmp getNumLoop
move_back:
cpx #$15
beq getNumLoop
jsr CHROUT
jmp getNumLoop
move_left:
cpx #$15 ; first digit
beq getNumLoop
jsr CHROUT
jmp getNumLoop
move_right:
cpx #$16 ; second digit
beq getNumLoop
jsr CHROUT
jmp getNumLoop
move:
sec
jsr PLOT
ldx #$15 ; first degit
clc
jsr PLOT
sec
jsr PLOT
clc
sbc #$2F ; to calculate it, it should be subtracted by #$2f
asl
asl
asl
asl
pha
ldx #$16
clc
jsr PLOT
sec
jsr PLOT
clc
sbc #$2F ; to calculate it, it should be subtracted by #$2f
pha
ldx #$00
iny
clc
jsr PLOT
sec
jsr PLOT
pla
tax
pla
rts
; store the first number
storeFirstNum:
sta NUM1
txa
eor NUM1
sta NUM1
rts
; store the second number
storeSecondNum:
sta NUM2
txa
eor NUM2
sta NUM2
rts
; print out the result
printResult:
sec
jsr PLOT
ldx #$15
clc
jsr PLOT
sec
jsr PLOT
sed
lda NUM1
adc NUM2
cld
pha
bcc outputAddition
ldx #$14
clc
jsr PLOT
sec
jsr PLOT
lda #$31
jsr CHROUT
; calculation of the two number
outputAddition:
lsr
lsr
lsr
lsr
clc
adc #$30 ; as the received number does not fit for ASCII, it needs to add #$30
jsr CHROUT
pla
and #$0F
clc
adc #$30 ; as the received number does not fit for ASCII, it needs to add #$30
jsr CHROUT
sec
jsr PLOT
ldx #$00
iny
clc
jsr PLOT
rts
; prompt to get first number, format "00"
firstNumPrint:
lda firstNum,y
beq goback_main
jsr CHROUT
iny
bne firstNumPrint
; prompt to get the second number, format "00"
secondNumPrint:
lda secondNum,y
beq goback_main
jsr CHROUT
iny
bne secondNumPrint
; print our the result line
resultPrintString:
lda result,y
beq goback_main
jsr CHROUT
iny
bne resultPrintString
; go back to the "mainLoop"
goback_main:
rts
firstNum:
dcb "E","N","T","E","R",32,"F","I","R","S","T",32,"N","U","M","B","E","R",":",32,32,"0","0"
dcb 00
secondNum:
dcb "E","N","T","E","R",32,"S","E","C","O","N","D",32,"N","U","M","B","E","R",":",32,"0","0"
dcb 00
result:
dcb "R","E","S","U","L","T",":"
dcb 00
What I have learned from this lab?
This lab definitely takes a lot of my time, I always encounter error related to subroutines. Since I am not used to Assembly Language yet, however, this is why I have to spend some times working on it.
đź’– đź’Ş đź™… đźš©
Thanh Van
Posted on November 4, 2021
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