Simple Pub-Sub System using Redis and Python

rohit20001221

rohit20001221

Posted on March 27, 2022

Simple Pub-Sub System using Redis and Python

Hi guys i am here with an another blog post now let us build a simple publish subscribe system using python and redis

Running the redis server

i am using docker to start a redis instance in my computer. it's very easy to run a redis instance using docker and also it's very easy to remove redis instance, and the fun part is redis running through docker would not affect our system πŸ˜„

running redis instance



docker run --name demo-redis -p 6379:6379 -d redis:alpine


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if you want to stop or remove redis instance running through above command you can do the following



docker container stop demo-redis # <-- stop the redis instance

docker container rm demo-redis # <-- remove the redis container


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Creating the publisher



import redis

# initializing the redis instance
r = redis.Redis(
    host='127.0.0.1',
    port=6379,
    decode_responses=True # <-- this will ensure that binary data is decoded
)

while True:
    message = input("Enter the message you want to send to soilders: ")

    r.publish("army-camp-1", message)


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let's think publisher as a commander in army and he wants to send message to the soilders so here the the topic that he wants to publish message is army-camp-1. this analogy is only for fun πŸ˜‚

Creating the subscriber



import redis

r = redis.Redis(
host='127.0.0.1',
port=6379,
decode_responses=True
)

# pubsub() method creates the pubsub object

but why i named it mobile 🧐

just kidding πŸ˜‚ think of it as the waki taki that listens for incomming messages

mobile = r.pubsub()

# use .subscribe() method to subscribe to topic on which you want to listen for messages
mobile.subscribe('army-camp-1')

# .listen() returns a generator over which you can iterate and listen for messages from publisher

for message in mobile.listen():
print(message) # <-- you can literally do any thing with this message i am just printing it

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Here is a demo video of running the above code

πŸ’– πŸ’ͺ πŸ™… 🚩
rohit20001221
rohit20001221

Posted on March 27, 2022

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