rikoroku
Posted on July 30, 2020
I will show you a way, what how to use LIKE operator with AngularFire.
This post is based on this.
ng version
Angular CLI: 9.0.2
Node: 12.16.0
Package Version
-----------------------------------------------------------
@angular-devkit/core 9.0.2
@angular/cli 9.0.2
@angular/fire 6.0.0-rc.1
codes
src/app/models/user.model.ts
export class User {
id: string;
name: string;
createdAt: Date;
}
src/app/services/user.service.ts
import { Injectable } from "@angular/core";
import { AngularFirestore } from "@angular/fire/firestore";
import { User } from "src/app/models/user.model";
@Injectable()
export class UserService {
constructor(private firestore: AngularFirestore) {}
findUsers(name: string) {
// 'users' is a name of users collection on Firestore
return this.firestore.collection<User>('users', ref => { return ref.orderBy('name').startAt(name).endAt(name+'\uf8ff') }).snapshotChanges();
}
}
src/app/components/user/user.component.ts
import { Component, OnInit } from "@angular/core";
import { UserService } from "src/app/services/user.service";
@Component({
selector: "app-user",
templateUrl: "./user.component.html",
styleUrls: ["./user.component.scss"]
})
export class UserComponent implements OnInit {
constructor(private uService: UserService) {}
ngOnInit(): void {}
search() {
this.uService.findUsers("A part of the user name you want to find").subscribe(data => {
console.log(data)
});
}
}
Above codes are now working completely.
I hope that this post helps you for using LIKE operator with AngularFire.
If you got some problems. Don't be confused. Please share me with information about errors. I will teach you how to fix it.
Thank you for reading.
💖 💪 🙅 🚩
rikoroku
Posted on July 30, 2020
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