// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

Input: nums = [3,2,2,3], val = 3
Output: 2, nums = [2,2]
Explanation: Your function should return length = 2, with the first two elements of nums being 2.
It doesn't matter what you leave beyond the returned length. For example if you return 2 with nums = [2,2,3,3] or nums = [2,2,0,0], your answer will be accepted.

Input: nums = [0,1,2,2,3,0,4,2], val = 2
Output: 5, nums = [0,1,4,0,3]
Explanation: Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4. Note that the order of those five elements can be arbitrary. It doesn't matter what values are set beyond the returned length.

var removeElement = function(nums, val) {
    // iterate over nums from last index to 0th
    // remove nums that equal val

    //return lengths of nums
};

var removeElement = function(nums, val) {
    // iterate over nums from last index to 0th
    // remove nums that equal val
    for (let i=nums.length-1; i>=0; i--) {
        if (nums[i] === val) {
            nums.splice(i,1)
        }
    }

    //return lengths of nums
    return nums.length
};