862. Shortest Subarray with Sum at Least K
MD ARIFUL HAQUE
Posted on November 17, 2024
862. Shortest Subarray with Sum at Least K
Difficulty: Hard
Topics: Array
, Binary Search
, Queue
, Sliding Window
, Heap (Priority Queue)
, Prefix Sum
, Monotonic Queue
Given an integer array nums
and an integer k
, return the length of the shortest non-empty subarray of nums
with a sum of at least k
. If there is no such subarray, return -1
.
A subarray is a contiguous part of an array.
Example 1:
- Input: nums = [1], k = 1
- Output: 1
Example 2:
- Input: nums = [1,2], k = 4
- Output: -1
Example 3:
- Input: nums = [2,-1,2], k = 3
- Output: 3
Constraints:
1 <= nums.length <= 105
-105 <= nums[i] <= 105
1 <= k <= 109
Solution:
We need to use a sliding window approach combined with prefix sums and a monotonic queue. Here's the step-by-step approach:
Steps:
-
Prefix Sum:
- First, calculate the prefix sum array, where each element at index
i
represents the sum of the elements from the start of the array toi
. The prefix sum allows us to compute the sum of any subarray in constant time.
- First, calculate the prefix sum array, where each element at index
-
Monotonic Queue:
- We use a deque (double-ended queue) to maintain the indices of the
prefix_sum
array. The deque will be maintained in an increasing order of prefix sums. - This helps us efficiently find subarrays with the sum greater than or equal to
k
by comparing the current prefix sum with earlier prefix sums.
- We use a deque (double-ended queue) to maintain the indices of the
-
Sliding Window Logic:
- For each index
i
, check if the difference between the current prefix sum and any previous prefix sum (which is stored in the deque) is greater than or equal tok
. - If so, compute the length of the subarray and update the minimum length if necessary.
- For each index
Algorithm:
- Initialize
prefix_sum
array with sizen+1
(wheren
is the length of the input array). The first element is0
because the sum of zero elements is0
. - Use a deque to store indices of
prefix_sum
values. The deque will help to find the shortest subarray that satisfies the condition in an efficient manner. - For each element in the array, update the
prefix_sum
, and check the deque to find the smallest subarray with sum greater than or equal tok
.
Let's implement this solution in PHP: 862. Shortest Subarray with Sum at Least K
<?php
/**
* @param Integer[] $nums
* @param Integer $k
* @return Integer
*/
function shortestSubarray($nums, $k) {
...
...
...
/**
* go to ./solution.php
*/
}
// Example usage:
$nums1 = [1];
$k1 = 1;
echo shortestSubarray($nums1, $k1) . "\n"; // Output: 1
$nums2 = [1, 2];
$k2 = 4;
echo shortestSubarray($nums2, $k2) . "\n"; // Output: -1
$nums3 = [2, -1, 2];
$k3 = 3;
echo shortestSubarray($nums3, $k3) . "\n"; // Output: 3
?>
Explanation:
-
Prefix Sum Array:
- We compute the cumulative sum of the array in the
prefix_sum
array. This helps in calculating the sum of any subarraynums[i...j]
by using the formulaprefix_sum[j+1] - prefix_sum[i]
.
- We compute the cumulative sum of the array in the
-
Monotonic Queue:
- The deque holds indices of the
prefix_sum
array in increasing order of values. We maintain this order so that we can efficiently find the smallest subarray whose sum is greater than or equal tok
.
- The deque holds indices of the
-
Sliding Window Logic:
- As we traverse through the
prefix_sum
array, we try to find the smallest subarray using the difference between the currentprefix_sum[i]
and previousprefix_sum[deque[0]]
. - If the difference is greater than or equal to
k
, we calculate the subarray length and update the minimum length found.
- As we traverse through the
-
Returning Result:
- If no valid subarray is found, return
-1
. Otherwise, return the minimum subarray length.
- If no valid subarray is found, return
Time Complexity:
-
Time Complexity:
O(n)
, wheren
is the length of the input array. Each element is processed at most twice (once when added to the deque and once when removed). -
Space Complexity:
O(n)
due to theprefix_sum
array and the deque used to store indices.
This approach ensures that the solution runs efficiently even for large inputs.
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Posted on November 17, 2024
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