1310. XOR Queries of a Subarray
MD ARIFUL HAQUE
Posted on September 13, 2024
1310. XOR Queries of a Subarray
Difficulty: Medium
Topics: Array
, Bit Manipulation
, Prefix Sum
You are given an array arr
of positive integers. You are also given the array queries
where queries[i] = [lefti, righti]
.
For each query i
compute the XOR of elements from lefti
to righti
(that is, arr[lefti] XOR arr[lefti + 1] XOR ... XOR arr[righti]
).
Return an array answer
where answer[i]
is the answer to the ith query.
Example 1:
- Input: arr = [1,3,4,8], queries = [[0,1],[1,2],[0,3],[3,3]]
- Output: [2,7,14,8]
- Explanation: The binary representation of the elements in the array are:
1 = 0001
3 = 0011
4 = 0100
8 = 1000
The XOR values for queries are:
[0,1] = 1 xor 3 = 2
[1,2] = 3 xor 4 = 7
[0,3] = 1 xor 3 xor 4 xor 8 = 14
[3,3] = 8
Example 2:
- Input: arr = [4,8,2,10], queries = [[2,3],[1,3],[0,0],[0,3]]
- Output: [8,0,4,4]
Constraints:
1 <= arr.length, queries.length <= 3 * 104
1 <= arr[i] <= 109
queries[i].length == 2
0 <= lefti <= righti < arr.length
Hint:
- What is the result of x ^ y ^ x ?
- Compute the prefix sum for XOR.
- Process the queries with the prefix sum values.
Solution:
We can make use of the prefix XOR technique. Here's how it works:
Approach:
Prefix XOR Array: We compute a prefix XOR array where
prefix[i]
represents the XOR of all elements from the start of the array up to indexi
. This allows us to compute the XOR of any subarray in constant time.-
XOR of a subarray:
- To compute the XOR of elements between indices
left
andright
:- If
left > 0
, we can compute the XOR fromleft
toright
asprefix[right] ^ prefix[left - 1]
. - If
left == 0
, then the result is simplyprefix[right]
.
- If
- To compute the XOR of elements between indices
This allows us to answer each query in constant time after constructing the prefix XOR array.
Plan:
- Build the prefix XOR array.
- For each query, use the prefix XOR array to compute the XOR for the range
[left_i, right_i]
.
Let's implement this solution in PHP: 1310. XOR Queries of a Subarray
<?php
/**
* @param Integer[] $arr
* @param Integer[][] $queries
* @return Integer[]
*/
function xorQueries($arr, $queries) {
...
...
...
/**
* go to ./solution.php
*/
}
// Example 1
$arr1 = [1, 3, 4, 8];
$queries1 = [[0, 1], [1, 2], [0, 3], [3, 3]];
print_r(xorQueries($arr1, $queries1)); // Output: [2, 7, 14, 8]
// Example 2
$arr2 = [4, 8, 2, 10];
$queries2 = [[2, 3], [1, 3], [0, 0], [0, 3]];
print_r(xorQueries($arr2, $queries2)); // Output: [8, 0, 4, 4]
?>
Explanation:
-
Prefix XOR Construction:
- The array
prefix
is built such thatprefix[i]
contains the XOR of all elements fromarr[0]
toarr[i]
. - For example, given
arr = [1, 3, 4, 8]
, theprefix
array will be[1, 1^3, 1^3^4, 1^3^4^8]
or[1, 2, 6, 14]
.
- The array
-
Answering Queries:
- For each query
[left, right]
, we compute the XOR of the subarrayarr[left]
toarr[right]
using:-
prefix[right] ^ prefix[left - 1]
(ifleft > 0
) -
prefix[right]
(ifleft == 0
)
-
- For each query
Time Complexity:
-
Building the prefix array: O(n), where
n
is the length of thearr
. -
Processing the queries: O(q), where
q
is the number of queries. - Overall Time Complexity: O(n + q), which is efficient for the given constraints.
This approach ensures we can handle up to 30,000 queries on an array of size up to 30,000 efficiently.
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Posted on September 13, 2024
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