Question

Given two lists, l1 and l2, write a program to create a third list l3 by picking an odd-index element from the list l1 and even index elements from the list l2.

Given:

l1 = [3, 6, 9, 12, 15, 18, 21]
l2 = [4, 8, 12, 16, 20, 24, 28]

Expected Output:

Element at odd-index positions from list one
[6, 12, 18]
Element at even-index positions from list two
[4, 12, 20, 28]

Printing Final third list
[6, 12, 18, 4, 12, 20, 28]

My solution

use the list comprehension
use enumerate() function to generate index and value for each element in each list
find the remainder of the index divided by two
- if remainder is not zero mean an odd index
  - i.e. "if index % 2" is not equal to 0, so it would equal to True
- if the remainder is zero mean an even index
  - i.e. if index % 2 is 0, so would equal to false
  - list comprehension only accept True condition,
  - so "not index % 2" is used

l1 = [3, 6, 9, 12, 15, 18, 21]  
l2 = [4, 8, 12, 16, 20, 24, 28]  
odd_index_list = [num for index, num in enumerate(l1) if index % 2]  
print("Element at odd-index positions from list one")  
print(odd_index_list)  

even_index_list = [num for index, num in enumerate(l2) if not index % 2]  
print("Element at even-index positions from list two")  
print(even_index_list)  

final_list = odd_index_list + even_index_list  
print("Printing Final third list")  
print(final_list)

Other solution

use string slicing method
for odd elements slice the string from index 1 to the end with a step of 2
for even elements slice the string form index 0 to the end with a step of 2

list1 = [3, 6, 9, 12, 15, 18, 21]
list2 = [4, 8, 12, 16, 20, 24, 28]
res = list()

odd_elements = list1[1::2]
print("Element at odd-index positions from list one")
print(odd_elements)

even_elements = list2[0::2]
print("Element at even-index positions from list two")
print(even_elements)

print("Printing Final third list")
res.extend(odd_elements)
res.extend(even_elements)
print(res)

Credit

exercise on Pynative

Blog

Python Exercise 10: Generate a list based on odd or even index

HHMathewChan

Question

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