Inverting Map of Map in functional way
Ingun 전인건
Posted on July 25, 2021
This post is about implementing a function for inverting Map of Maps, that is,
(typescript)
Map<A, Map<B, T>>
// to
Map<B, Map<A, T>>
I’ll be using Haskell and Typescript throughout the post and show my best attempt in the end.
Table of Contents
Motivation
Recently I got to deal with lots of instances of a type T
. Since there were so many of them, I had to group them by some criterion for performance reasons. For example, T
uses resource A
so I group T
s by A
thereby I can process all the T
s that share the same A
at once when it is allocated.
In my case there were two criteria, A
and B
, that I had to take into account simultaneously so naturaly I got to build a data structure of
(typescript)
Map<A, Map<B, T[]>>
(haskell)
Map A (Map B [T])
The problem was that in some cases it needed to be expressed in the form of Map<B, Map<A, T[]>>
which is alteration of switching the outter Map’s Key and inner Map’s Key.
Of course I could just implement it imperatively something like this …
(pseudo imperative code)
// boring imperative code …
func invertMap(ABTs: Map<A, Map<B, T[]>>):
BATs = new Map<B, Map<A, T[]>>
for (a, BTs) of ABTs:
for (b, Ts) of BTs:
if BATs has no key b then
BATs[b] = new Map<A, T[]>
BATs[b][a] = Ts
else
if BATs[b] has no key a then
BATs[b][a] = Ts
else
BATs[b][a].add Ts
return BATs
But I thought I could do better. They were the algebraically same data structure therefore there must have been a natural way of transforming into each other. I only needed to find them.
Applicative Map?
At first I thought about conforming Map<B, _>
to Applicative then just sequence
ing it. It was possible because Map is Traversable. But soon I found Map couldn’t conform to Applicative because there is simply no way to implement pure
(or of
, if you will) nor ap
(or <*>
, liftA
, if you will). I mean how are you going to construct a Map of functions that satisfies Identity law?!
So I gave up on Applicative Map.
Combining Monoidal Operations
I got thinking that it was evident in the imperative version of implementation above that the whole process is just combination of Monoidal operations: creating empty Map, concatenating list of Ts and ultimately combining all to define monoidal operation on Map<B, Map<A, T>>
.
This observation led me to this functional implementation.
Implementation
(Haskell)
invertMap :: (Monoid t, Ord a, Ord b) => Map a (Map b t) -> Map b (Map a t)
invertMap = foldr (unionWith mappend) empty . mapWithKey (fmap . singleton)
(Typescript, fp-ts)
export function invertMap<KA, KB, T>(
kaOrd: Eq<KA>,
kbOrd: Eq<KB>,
monT: Monoid<T>
) {
const monAT = map.getMonoid(kaOrd, monT);
const monBAT = map.getMonoid(kbOrd, monAT);
return (mm: Map<KA, Map<KB, T>>) =>
getFoldableWithIndex(kaOrd).foldMapWithIndex(monBAT)(mm, (a, bt) =>
pipe(
bt,
map.map((t) => new Map<KA, T>().set(a, t))
)
);
}
Posted on July 25, 2021
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