JavaScript Default Function Parameters.
Syed Mohsin Raza
Posted on November 30, 2021
In JavaScript when we call a function which expects some data to be passed in if you call that without passing in that data JavaScript will use undefined.
Let's understand this practically ⚙️
What the following function does is that it takes a name as an input and console logs it.
function printName(name) {
console.log(name);
}
Now if we call the printName
function by passing in a name as shown below:
printName("frontendenthusiast");
We'll get the following output.
frontendenthusiast
Now lets call the same function without passing anything in
printName();
We will get undefined
as the output in the console.
undefined
undefined
isn't that useful in most situations what if we can use a fallback if no name is passed into the function. Well for that we can use the ||
operator in JavaScript as shown below:
function printName(name) {
name = name || `Anonymous`;
console.log(name);
}
The Logical OR (||) operator returns the very first truthy value and undefined is a falsy value so in the printName
function it will return Anonymous which is a truthy value.
Now with the above addition of ||
operator if we call the function by passing in no value as shown:
printName();
We will get Anonymous
as the output.
Anonymous
In ES6 we have a more compact way of doing the above which is to set up default parameters directly using the assignment operator =
as shown:
function printName(name = `Anonymous`) {
console.log(name);
}
this returns default value we set using =
operator in case no value was passed in.
function printName(name = `frontendenthusiast`) {
console.log(name);
}
printName(undefined);
The output of the above function will be frontendenthusiast
Happy coding! 🥰
Posted on November 30, 2021
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