LeetCode 139. Word Break (javascript solution)

Description:

Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or more dictionary words.

Note that the same word in the dictionary may be reused multiple times in the segmentation.

Solution:

Time Complexity : O(wordDict.length*s.length^2)
Space Complexity: O(s.length^2)

var wordBreak = function(s, wordDict, memo={}) {
    // If we have s stored in memo return its value
    if(memo[s]!==undefined) return memo[s]
    // We can always make and empty string 
    if(s.length===0) return true   

    for(const word of wordDict) {
        // Check if word is at the beginning of s
        if(s.indexOf(word)===0) {
            // Recursive call to check if using word as the prefix is a possible combination to complete s
            const output = wordBreak(s.slice(word.length), wordDict, memo)
            if(output) {
                // If we are able to complete s save in memo as true
                memo[s] = true
                return true
            }
        }
    }

    // If we get here then we did not find combinations to complete s using wordDict
    memo[s] = false
    return false
};

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LeetCode 139. Word Break (javascript solution)

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Description:

Solution:

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