102. Binary Tree Level Order Traversal (javascript solution)
codingpineapple
Posted on May 7, 2021
Description:
Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level).
Solution:
Time Complexity : O(n)
Space Complexity: O(n)
// BFS
var levelOrder = function(root) {
if(!root) return []
const queue = []
const output = []
queue.push(root)
while(queue.length) {
// Remove all the current nodes in the queue and add each node's children to the queue
const len = queue.length
const row = []
for(let i = 0; i < len; i++) {
const cur = queue.shift()
if(cur.left) queue.push(cur.left)
if(cur.right) queue.push(cur.right)
// Push the current node val to the row array
row.push(cur.val)
}
// Push the current row array into the output array
output.push(row)
}
return output
};
π πͺ π
π©
codingpineapple
Posted on May 7, 2021
Join Our Newsletter. No Spam, Only the good stuff.
Sign up to receive the latest update from our blog.
Related
sorting Recap the highlight of the sorting algorithms using JavaScript for beginners
October 5, 2024
datastructures DSA with JS: Understanding Custom Array Data Structure in JavaScript - A Step-by-Step Guide
September 29, 2024