Classes, Not Just Syntactic Sugar
Parwinder 👨🏻💻
Posted on September 4, 2020
We went over classes in the last blog post and how they make it easier to create objects using a blueprint. The class
keyword was introduced in ES2015/ES6, and there is a common misconception that classes are barely syntactic sugar and nothing more. Classes are the core fundamentals of object-oriented programming. My aim with this blog post is to demystify the misconception and showcase how classes are slightly different from functions paired with new
keyword.
What does a class do?
class EmployeeRecord {
name = "New User";
id = 0;
constructor(firstName, lastName, id) {
this.name = `${firstName} ${lastName}`;
this.id = id;
}
reverseName() {
return this.name.split("").reverse().join("");
}
}
const employee1 = new EmployeeRecord("Parwinder", "Bhagat", 1);
const employee2 = new EmployeeRecord("Lauren", "L", 2);
console.log(employee1.name); // Parwinder Bhagat
console.log(employee2.name); // Lauren L
console.log(employee1.reverseName()); // tagahB redniwraP
In the above class
example:
- Under the hood, a function called
EmployeeRecord
is created. The function body is made of the constructor of the class. If there is no constructor, then the function body is empty. - All the class methods are stored on the prototype of
EmployeeRecord
.
With that logic, we can re-write the above class without using classes or the class
keyword.
function EmployeeRecord(firstName, lastName, id) {
this.name = `${firstName} ${lastName}`;
this.id = id;
}
EmployeeRecord.prototype.reverseName = function () {
return this.name.split("").reverse().join("");
}
let employee1 = new EmployeeRecord("Parwinder", "Bhagat", 1);
const employee2 = new EmployeeRecord("Lauren", "L", 2);
console.log(employee1.name); // Parwinder Bhagat
console.log(employee2.name); // Lauren L
console.log(employee1.reverseName()); // tagahB redniwraP
The results are the same and this is where class
is just syntactic sugar comes from.
How do classes differ?
- There is a specific function kind assigned to classes and it is checked at multiple places most importantly whenever we instantiate a class.
class EmployeeRecord {
constructor() { }
}
console.log(typeof EmployeeRecord); // function
EmployeeRecord(); // Value of type 'typeof EmployeeRecord' is not callable. Did you mean to include 'new'?
- Functional inheritance works using the prototype. Classes do the same using a cleaner syntax with
extends
keyword.
class Person {
sayName() {
console.log("My name is Person");
}
sayAge() {
console.log("I am 30 years old."); // I am 30 years old.
}
}
class Employee extends Person {
sayDepartment() {
console.log("I work for the tech department."); // I work for the tech department.
}
sayHello() {
console.log("Hi, I am the new employee"); // Hi, I am the new employee
}
}
let employee = new Employee;
employee.sayHello();
employee.sayAge();
employee.sayDepartment();
console.log(employee instanceof Person); // true
console.log(employee instanceof Employee); // true
- Function declarations are hoisted, and class declarations are not!
const employee = new Employee(); // ReferenceError or Employee is not a constructor
class Employee {
constructor() {}
}
A class always runs in strict mode. All code inside the class is automatically in strict mode.
Function decelerations and expressions can be overridden as they are similar to a
var
whereas classes are not overridden. They are likelet
andconst
keywords, let does not allow multiple declarations with the same name inside its scope.Objects can have (non-enumerable) properties that do not show up when iterated through that object. Class methods are non-enumerable and have the enumerable property set to false. If we use
for..in
to loop over an object from a class, we will not get the methods.
Posted on September 4, 2020
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