10 Algos 🚀 to Boost Your JavaScript Skills 🦄

awedis

awedis

Posted on February 9, 2022

10 Algos 🚀 to Boost Your JavaScript Skills 🦄

1) Find the missing number in the array

Input: [1, 2, 3, 4, 6, 7, 8, 9, 10]
Output: 5
Enter fullscreen mode Exit fullscreen mode
const find_missing = function(input) {
  let n = input.length + 1;

  let sum = 0;
  for (let i in input) {
    sum += input[i];
  }

  return Math.floor((n * (n + 1)) / 2) - sum;
};
Enter fullscreen mode Exit fullscreen mode

Hint: Arithmetic series sum formula:
Image description

2) Reverse Integer

Input: num = 123
Output: 321
Input: num = -123
Output: -321
Enter fullscreen mode Exit fullscreen mode
const reverse = function(num) {
    let result = 0;
    while (num !== 0) {
      result = result * 10 + num % 10;
      num = Math.trunc(num / 10);
    }

    if (result > 2**31 || result < -(2**31)) return 0;
    return result;
};
Enter fullscreen mode Exit fullscreen mode

3) Array Permutations

Input: [1,2,3]
Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Enter fullscreen mode Exit fullscreen mode
const permute = function(nums) {
    let results = [];

    let go = (current) => {
      if (current.length === nums.length){
        results.push(current);
        return;
      }
      nums.forEach(n => {
        if (!current.includes(n)){
          go([...current, n]);
        }
      });
    }
    go([]);
    return results;
};
Enter fullscreen mode Exit fullscreen mode

4) Permutation in String

Input: s1 = "ab", s2 = "eidbao"
Output: true
Input: s1 = "aa", s2 = "eidbao"
Output: false
Enter fullscreen mode Exit fullscreen mode
const checkPermutation = function(s1, s2) {
  const len1 = s1.length, len2 = s2.length;
  if (len1 > len2) return false;

  const count = Array(26).fill(0);
  for (let i = 0; i < len1; i++) {
      count[s1.charCodeAt(i)-97]++;
      count[s2.charCodeAt(i)-97]--;
  }
  if (!count.some(e => e !== 0)) return true;

  for (let i = len1; i < len2; i++) {
      count[s2.charCodeAt(i)-97]--;
      count[s2.charCodeAt(i-len1)-97]++;
      if (!count.some(e => e !== 0)) return true;
  }
  return false;
};
Enter fullscreen mode Exit fullscreen mode

5) Longest Valid Parentheses

Input: "(()"
Output: 2
Input: ")()())"
Output: 4
Enter fullscreen mode Exit fullscreen mode
const longestValidParentheses = function(S) {
  let stack = [-1], ans = 0;
  for (let i = 0; i < S.length; i++)
    if (S[i] === '(') stack.push(i)
    else if (stack.length === 1) stack[0] = i
    else stack.pop(), ans = Math.max(ans, i - stack[stack.length-1])
  return ans
};
Enter fullscreen mode Exit fullscreen mode

6) 4Sum

const fourSum = function(nums, target) {
  let result = [];
  let length = nums.length;
  if (length < 4) return result; 
  nums = nums.sort((a, b) => a - b );

  for (let i = 0; i < length - 3; i++) {
    if (nums[i] === nums[i - 1]) continue;
    for (let j = i + 1; j < length - 2; j++) {
      if (j > i + 1 && nums[j] === nums[j - 1]) continue;

      let k = j + 1;
      let l = length - 1;

      while (k < l) {
        const sum = nums[i] + nums[j] + nums[k] + nums[l];

        if (sum === target) {
          result.push([nums[i], nums[j], nums[k], nums[l]])
        }

        if (sum <= target) {
          k += 1;
          while (nums[k] === nums[k - 1]) {
            k += 1;
          }
        }

        if (sum >= target) {
          l -= 1;
          while (nums[l] === nums[l + 1]) {
            l -= 1;
          }
        }
      }
    }
  }

  return result;
};
Enter fullscreen mode Exit fullscreen mode

7) Multiply Strings

Input: num1 = "2", num2 = "3"
Output: "6"
Enter fullscreen mode Exit fullscreen mode
const multiply = function(num1, num2) {
    if (num1 == 0 || num2 == 0) return '0';
    const result = [];

    for (let a = num1.length - 1; a >= 0; a--) {
        for (let b = num2.length - 1; b >= 0; b--) {
            const p1 = a + b;
            const p2 = a + b + 1;
            const sum = (result[p2] ?? 0) + num1[a] * num2[b];

            result[p1] = (result[p1] ?? 0) + Math.floor(sum / 10);
            result[p2] = sum % 10;
        }
    }
    result[0] == 0 && result.shift();
    return result.join('');
};
Enter fullscreen mode Exit fullscreen mode

8) Shortest Palindrome

Input: s = "aacecaaa"
Output: "aaacecaaa"
Input: s = "abcd"
Output: "dcbabcd"
Enter fullscreen mode Exit fullscreen mode
const shortestPalindrome = function(s) {
  let index = 0;
  for (let i = s.length - 1; i >= 0; i--) {
    if (s[i] === s[index]) index++;
  }
  if (index === s.length) return s;
  let remainingRev = s.substring(index, s.length);
  console.log(remainingRev);
  remainingRev = reverse(remainingRev);

  return remainingRev + shortestPalindrome(s.substring(0, index)) + s.substring(index);
};

function reverse(string) {
  let myString = '';
  for (let i = string.length - 1; i >= 0; i--) {
    myString = myString + string[i];
  }
  return myString;
};
Enter fullscreen mode Exit fullscreen mode

9) Integer to English Words

Input: num = 123
Output: "One Hundred Twenty Three"
Input: num = 1234567
Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
Enter fullscreen mode Exit fullscreen mode
const numberToWords = function(num) {
  let result = toHundreds(num % 1000);
  const bigNumbers = ["Thousand", "Million", "Billion"];
  for (let i = 0; i < 3; ++i) {
    num = Math.trunc(num / 1000);
    result = num % 1000 !== 0 ? [toHundreds(num % 1000), bigNumbers[i], result].filter(Boolean).join(" ") : result;
  }
  return result.length === 0 ? "Zero" : result;
}

function toHundreds(num) {
  const numbers = ["", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
    "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"];
  const tens = ["", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"];
  const result = Array(3).fill("");
  let a = Math.trunc(num / 100), b = num % 100, c = num % 10;
  result[0] = a > 0 && `${numbers[a]} Hundred`;
  result[1] = b < 20 ? numbers[b] : tens[Math.trunc(b / 10)]
  result[2] = b >= 20 && `${numbers[c]}`;
  return result.filter(Boolean).join(" ");
}
Enter fullscreen mode Exit fullscreen mode

10) Ransom Note

Input: ransomNote = "aa", magazine = "ab"
Output: false
Input: ransomNote = "aa", magazine = "aab"
Output: true
Enter fullscreen mode Exit fullscreen mode
const canConstruct = function(ransomNote, magazine) {
  if (ransomNote.length > magazine.length) return false;
  let magMap = new Map();

  for(let char of magazine) {
    magMap.set(char, (magMap.get(char) || 0 ) + 1);
  }

   for(let note of ransomNote) {
    let counter = magMap.get(note);
    if (!counter) return false;

    magMap.set(note, --counter);
   }
  return true;
};
Enter fullscreen mode Exit fullscreen mode

After doing some research, I came out with these 10 algorithms, each of them have special tricks that not only will increase our JavaScript skills, but it will also help us to improve our critical thinking ability 🙂

💖 💪 🙅 🚩
awedis
awedis

Posted on February 9, 2022

Join Our Newsletter. No Spam, Only the good stuff.

Sign up to receive the latest update from our blog.

Related